Sqr(x^2-5x+3)+sqr(x^2-5x+10)=7

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Solution for Sqr(x^2-5x+3)+sqr(x^2-5x+10)=7 equation: 


Simplifying
Sqr(x2 + -5x + 3) + sqr(x2 + -5x + 10) = 7

Reorder the terms:
qrS(3 + -5x + x2) + sqr(x2 + -5x + 10) = 7
(3 * qrS + -5x * qrS + x2 * qrS) + sqr(x2 + -5x + 10) = 7
(3qrS + -5qrxS + qrx2S) + sqr(x2 + -5x + 10) = 7

Reorder the terms:
3qrS + -5qrxS + qrx2S + qrs(10 + -5x + x2) = 7
3qrS + -5qrxS + qrx2S + (10 * qrs + -5x * qrs + x2 * qrs) = 7
3qrS + -5qrxS + qrx2S + (10qrs + -5qrsx + qrsx2) = 7

Reorder the terms:
3qrS + 10qrs + -5qrsx + qrsx2 + -5qrxS + qrx2S = 7

Solving
3qrS + 10qrs + -5qrsx + qrsx2 + -5qrxS + qrx2S = 7

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Reorder the terms:
-7 + 3qrS + 10qrs + -5qrsx + qrsx2 + -5qrxS + qrx2S = 7 + -7

Combine like terms: 7 + -7 = 0
-7 + 3qrS + 10qrs + -5qrsx + qrsx2 + -5qrxS + qrx2S = 0

The solution to this equation could not be determined.

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